ECEELECTRICAL and COMPUTER ENGINEERING DEPARTMENTUniversity of Utah

              ECE 1270 - Introduction to Electrical and Computer Engineering

Grades


      Study Guides      Homework      Communications Assignments      Labs      Matlab      Practice Exams      


Instructor   TA

Dr. Angela Rasmussen
Email: ece1270@comcast.net
Office: MEB 3254

Office Hours:  R 9:30-11am

 

 

 

 

 

 

 

 

  Katie Furse (Monday/Tuesday Lab and Grader)

Email:  katiefurse@gmail.com
Phone:  (801)889-3206 (cell phone, text/call)
(801)583-0810 (home phone)

 

Eso Olakunle (Wednesday Lab)

Email:  kunleeso@gmail.com
Phone:  (801)502-9537 (cell phone, text/call)
 

 

 

 

     

Syllabus and Schedule

Notes:

On the following practice examples for the final, use R_T for the op-amp problems as a symbolic value and solve for  an equation for Vo.  Ignore other parts to that particular problem.

Final Exam Practice (Problem 1:  Linear Op Amps)

Final Exam Practice (Problem 2:  Op Amp with Choice of Element)

Final Exam Practice (Problem 3:  Thevenin equivalent for max power)

Final Exam Practice (Problem 4:  Frequency Domain Analysis)

Final Exam Practice (Extra Exam)

Final Exam Practice (All Together)        (missing) page44

 

 

 

 

 

 


Learning Objectives/Study Guides                            ECE


Homework                            ECE

The following is NOT free from errors!  Please email me if you find discrepancies in your work after triple checking it.

Homework

Modifications

Answers:

Due

 

 

 

 

Problem Set #1    Solution

Problem #5 change resistor 3ohm to 6.33ohm.  Problem #9 (b) find the power in the 3ohm resistor. 1. i1=16/155; i2=28/31; i3=-75/155; 3. a-b No, c-e Yes; 4. Ix=5A, 5. I1=6A, 6. Vc=19.3V, 7. i1=iaR2/(R3+R2); 8. i1=-Va/R2; 9. i1=3A; i2=9A; i3=1A; Vo=15V; P_3ohm=3W, P_supply=-234W, 10. i1=-0.2A; i2=.360A; i4=-0.56A, Vo=-7.3V. R, May 27

Problem Set #2    Solution

1.  i1 is through the 200ohm R.  1. i1=8mA,  2.V1=2V, 3.11kohm,  4.    (va+iaR2)(R1/R1+R2)R1, 5.power=i2^2R2, 6.  V1=(iaR3+Va)/(R3+R1(alpha+1)), 8. i3=(alphaVa)/((R1-alpha)(R2+R3)) 9.Vo=-(ia+Va/R1)R2, 10.  Vo=Va+iaR3 T, June 1

Problem Set #3    Solution

  1.  v1=4, v2=-5, v3=-1; 2. v1=-15, v2=-21, v3=-19, v4=-18, v5=-6; 6.  i1=-2, vo=-12; 7.  I=0.3A; 8.  v1=800/33; v2=40V; power_40=-315W; 9.  v1=-11.4, v2=28.6; 10.    v1=6/11, v2=-2/11 R, June 10

Problem Set #4    Solution

  1.  i1=-1/3, i2=-11/9, i3=7/9; 2.  Vx=93.3mV; power=5.2mW; 3.  Vth=10mV, Rth=504; 4.  Vth=-8/3; Rth=28/15, 5.  power=.62microW;  9.  Vth=(isR1R2)/(alpha-R1-R2), Rth=(R1R2)/(-alpha+R1+R2); 10.  power=-80W R, June 17

(Exam on Tues)

Problem Set #5    Solution

  1a.0A, b.125mA, c.-500pisin(2pix20xt)uV; 2a.0, b.105p, c.300ue^-t/2m; 3.never R, July 1

Problem Set #6    Solution

  1.  vo(t)=16-16e^-t/250u; 2.  i1(t)=-300ue-^t/2mA, i2(t)=300ue^-t/2m; 3.  v_phi(t)=-3.67+4.17e^-t/64mV; 4.  ib(t)=100uA; 5.  V1=(Vs+IsR3)/(R3*((1-alpha)/R2+(1/R3)+(1/R4))); 6.  wc=10nJ, V1(t)=-6.55e^-t/2.75uV; 7.  iL(t)=is(R3/(R3+R1||R2))+is(R3/(R1+R3)-R3/(R3+R1||R2))e^-t/L/(R3+R1||R2); 8.  RL=62.4k; 9.  62.4mW; 10.  i2=(vs+isR1||R3)/((1+alpha)R2+R1||R3) T, July 6

Problem Set #7    Solution

    T, July 20

Problem Set #8    Solution

 

1.R=2k, Vo=18/5sqrt(2) or L=2H, Vo=6/sqrt(2); 3.  R=50 4.Io=sqrt(2)/25, 5.Vth=-78j, 9. Vth=75+75j, Zth=5+5j  10.  L=62.5e-6H, Io=9sqrt(2)/2 T, July 27

Problem Set #9 and #10     Solution

 

  T, Aug 3

Problem Sessions                      

Homework Su09

 

 

 

Problem Set #1    Solution

Solution for #6

 

Problem Set #2    Solution

 

Problem Set #3    Solution

 

Problem Set #4    Solution

Solution Last Page

 

Problem Set #5    Solution

 

Problem Set #6    Solution

 

Problem Set #7    Solution

 

Problem Set #8    Solution

 
 

Problem Set #9    Solution

 
 

Problem Set #10    Solution

 

Communications Assignments                            ECE

·  Writing Assignments:

 

·  Oral Presentation:


Labs                            ECE


Matlab and Labview                            ECE


Practice Exams/Solutions                            ECE