Wireless Communication
Lecture 6 – Ground Reflection
Text Section 4.5,6
This is a review from basic EM. If you need additional information on this topic, please consult a basic electromagnetics text from the library.
TABLE 4.1
Characteristic impedance
Parallel and Perpendicular Polarization
Plane of Incidence: contains the rays marking the direction of propagation for the incident, transmitted, and reflected fields.
FIGURE 4.4 Plane of incidence is the paper/board
Parallel Polarization: E field is parallel to plane of incidence (A)\
Perpendicular Polarization: E field is perpendicular to plane of incidence (B)
Direction of Transmitted and Reflected waves:
From E field boundary conditions:
From Snell’s Law:
1=air
2=dielectric (ground or building)
(Note change of DEFINITION of angles from the ECE3170 textbook!)
(these may be complex)
When TX and RX are far apart, most of the ground bounces occur at “grazing” incidence (grazing the ground, both TX and RX nearly parallel to ground, very small qi)
Then G|| = 1 and G^ = -1
See Example3.4
(Ray-tracing theory … this is extended using computer programs to many rays, and can be combined with diffraction theory from the next section)
FIGURE 4.7
Eo = electric field a distance do from the transmitter
do = some small distance from the transmitter that is in the far field of the transmitter
E(d,t) = some electric field that we want to calculate
d = distance from the transmitter where we will calculate the field
t = instantaneous time where we are calculating the field
E(d,t) = (Eodo/d) cos(wc (t- d/c)) for d>do
Direct Path (LOS = Line of Sight)
E(d’,t) = (Eodo/d’) cos(wc (t- d’/c))
Path reflected off ground
E(d’’,t) = G (Eodo/d’’) cos(wc (t- d’’/c))
For d large:
G= -1 (perfect conductor, perpendicular polarization)
Total electric field
Etotal = ELOS + Eground
(this gives an exact equation for any t,d)
Approximation:
FIGURE 4.8
Difference in distance between the two paths…
First, no approximation:
Approximation:
Phase difference as a result of this difference in distance:
Time delay
For large distances, assume that the magnitudes of the waves stay the same, and only the phase changes:
Then the total field using the above approximations is:
(This is the time t that the field from the ground reflection arrives…)
Then the magnitude of this (approximate) total field is:
When qD is small
Then
Notes about Power Loss:
(1) This means that the power for a 2-ray model is falling off as d4 which is faster than the free-space value of d2
To analyze the power equation in dB instead of linearly:
Path Loss (dB)= (inverse of Pr)