ECE 1270 - Introduction to Electrical and Computer Engineering

                                Current Grades

 

Instructor

 

TA

Dr. Angela Rasmussen
Email: ece1270@comcast.net
Office: MEB 3254

Office Hours:  R 9:30-11am

  

 

 

 

 

Lucas Thomas (Lab TA)

Email:  lucacentric@gmail.com
Phone: 

 

Eso Olakunle (Grader)

Email:  kunleeso@gmail.com
Phone:  (801)502-9537 (cell phone, text/call)
 

NOTES:

Final Exam Practice (Problem 1:  Linear Op Amps)

Final Exam Practice (Problem 2:  Op Amp with Choice of Element)

Final Exam Practice (Problem 3:  Thevenin equivalent for max power)

Final Exam Practice (Problem 4:  Frequency Domain Analysis)

Final Exam Practice (Extra Exam)

Final Exam Practice (All Together)        (missing) page44

 

Notes before lecture Notes after lecture

Video
Unit 1 part 1 of 3 May 17     Independent Source
Unit 1 part 2 of 3 May 19 Dependent Source
Unit 1 part 3 of 3 May 24  
  May 26 Unit 2 Videos:
Unit 2 part 1 of 2 May 31 Node-Voltage
Unit 2 part 2 of 2 June 2 Mesh Currents (Ex1)
  June 7 Mesh Currents (Ex2)
  June 9 Thevenin Equivalent
Unit 3 part 1 of 2 June 14  
Unit 3 part 1 of 2 June 16  
  Exam 2 June 21  
  Watch Videos: Unit 3 Videos:
  June 28 Derivation of General Eq for Inductor.  Part 1
  June 30 Derivation of General Eq for Inductor.  Part 2
Unit 4 part 1 of 3 July 5 Derivation of General Eq for Capacitor
Unit 4 part 2 of 3 July 7 Inductor Example(independent sources)
Unit 4 part 3 of 3 No Notes Capacitor Example(independent sources)
  July 14 Inductor Example(dependent sources)
  July 19 Capacitor Example(dependent sources)
  July 21  
  July 26  
  July 28  
  August 2  

Learning Objectives/Study Guides                               

Homework                               

The following is NOT free from errors!  Please email me if you find discrepancies in your work after triple checking it.

Homework

Modifications

Answers:

Due

 

 

 

 

Problem Set #1    Solution

 #4.  Should read that the voltage is the same across the 2A source(not the 3A) 1.  i1=(375/57), i2=(45/57), i3=(70/19); 2.a) 30kW, b) 5.26kohm; 4.  Vc=95V, 5.I=6A; 6.  I2=-60/39, V4=-240/39; 7.  V1=[(Va-iaR3)*R1*R2]/[(R1+R2)R3+R1*R2]; 8.i1=iaR2/[R1(1-alpha)+R2]; 9.  i1=1/4A, i2=1A, i3=2/3A, Vo=10, power_24ohm=3/2W, power_6V=-23/2; 10.  i1=(10/11), i2=2,        i3=(-12/11), vo=(-156/11)

T, May 24

Problem Set #2    Solution

 New figure #10. 1.  i1=2A, 2.  V1=4V, 3.  Req=8.9kohm, 4.i1=(isR2-Vs)/(R1+R2); 5.  V1=[iaR3+Va]*R1/[R3+R1(1+alpha)], 6.  power=[[alpha(ia+Va)R1]/[1+R1(1+alpha]R2]^2*R2; 7.  Vo=Vs-i2R2; 8.  Vo=-Vs-isR1-[isR2R3/(R2+R3)]; 9.  Vo=Va+iaR3; 10.  Vo=Vs+isR4

T, May 31

Problem Set #3    Solution

 Find VB and VE for #9 and #10.

 1.c.  All currents going to the right or down direction:  I5k=-(4/5)mA, I6k=-(19/6)mA, I10k=-1mA, I7k=-1mA, I2k=(25/2)mA, I1k=-7mA; 3.  i1=1.43A, vo=-2,856V; 4.v1=-12.2, v2=-14.6; 6.  v1=5.2, v2=8.1, power_6V=-2.5W; 9.  VB=18.8, VE=3,608.7

R,  June 16

Problem Set #4    Solution

Solution Prob. 9

Solution Prob. 10

 

 1.  Vth=173, Rth=89.6; 2.  Vth=12.5, Rth=875; 9.  RTh = R1 + R2(1−α R1), Vth=Vs; 10.  power=3.3mW Sat, June 18

Problem Set #5    Solution

 

 1.  a)Vo=-30me^-(t/(9m/10)), b) 40.5nJ; 2.i1=-7.2me^-(t/4m), b) 0J; 3.iL=2e^-(t/0.03); 4.  V1=-7e^-(t/0.03); 5.  a)Vc=-18+24e^-(t/800m); 6.  V1=24V; 7.  V1=-42.8+42.8e^-(t/4m); 8.  Vo=-e^-(t/20m); 9.  VL=-21e^-(t/10m), iL=-(12/5)e^-(t/10m); 10.  i1=(-3/4)e^-(t/40micro) 

T, July 5

Problem Set #6    Solution Part 1

Solution Part 2

 

 1.  a)  w_L=2.43*10^-15J, b) V1=-5.4m-48.6me^-(t/0.5n); 2. Vc=Vs+[VsR2/(R1+R2)-Vs]e^-(t/(R1+R3)C); 3.  RL=1k, Power= 20.25mW; 4. i1=is/(1+alpha*R1);   5.a.  Vc=Vs+(IsR1-Vs)e^-(t/R2C), b) (1/2)CVs^2; 6.a.V1=[-Is+Vs/R2](R1||R2)e^-(t/(L/R1||R2)), b) (1/2)L(Vs/R2)^2; 7.i1=-3/2A; 8.Vo=50V; 9.RL=30, Power=19.2W 10.  RL=5k, power=956microW

M, July 11

Problem Set #7    Solution

 

 2.a.  (200-40j)/104; b.  2.8e4e^j18.4; c.  3e^-j15; d.  1.2; e.  -3.2m; 4.  -196j+102; 5.  6+0.99j; 7. is(t)=126mcos(2kt+40)A; 9.  v1(t)=447cos(1kt-153); 10. Ic=6.1cos(2kt-9.5)A

T, July 19

Problem Set #8    Solution

 

 1.a.  1+j, b.  3-j3sqrt(3), c.1/sqrt(2)cos(120kt-45), d.1, e.  4; 2.a.C=20mF; 3.  Vo=2; 4.  R=20k=> Io=1.2msqrt(2) or L=200H=>Io=600microsqrt(2); 5.Vth=12exp^(-j45), Zth=6k-6kj; 6.  Vth=-12, Zth=4; 7.  Vth=-VsRj/X1(Beta+1), Zth=R/(beta+1); 8.L=15mH, 9.  Vth=72exp^(j37), Zth=0.06exp^(j114); 10.  R=1k, Vo=2/1ksqrt(2)

T, July 26

Problem Set #9 and #10     Solution

 You do not need to do #3.

1.  Vo=Is2R4R6(R1+R2+R3)/(R1+R2)(R4+R5+R6)-is1(R1R3)/(R1+R2); b)R3=150k; c) Vo=idm*60k; d) Rin=1.2k;  2.  a=L=1mH, b=R=10k;  3.  I1=40, i(t)=40cos(377t)A, 4.  Vth=-1.2, Rth=2.4k; RL=2.4k, Pmax=150microW

R, Aug 4

 

Communications Assignments                               

  • CLEAR Center:
  • Writing Assignments:
  • Writing Center Help:
    • Location: 1st floor of Marriott Library.
    • Phone # to make reservations: 587-9122
  • Oral Presentation:
    • Oral presentation order (handed out in class only)

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